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  ■    What is the calculation of the electricity cost savings of pump energy consumption efficiency?    By:admin    
 
 
# How does the calculation of the energy cost savings of the pump energy consumption efficiency?
?? LA = (0.163 · S · Q · H) / (EA × EM)

LA: Shaft power of A pump ㎾
S: Specific gravity for water
Q: Output ㎥ / min
H: head m
Energy consumption efficiency of EA: A Pump
EM: energy consumption efficiency of prime movers

For example, when Q = 5m3 / min, H = 30m, S = 1, EA = 65%, EM = 90%, and EB = 75%

LA = (0.163 x 1 x 5 x 30) / (0.65 x 0.9) = 41.8 kW

LB = (0.163 x 1 x 5 x 30) / (0.75 x 0.9) = 36.2 kW



LA - LB = 41.8 - 36.2 = 5.6㎾: Reduced power

10 hours per day for 365 days Operation: 5.6㎾ × 10h × 365D = 20,440 [kwh]

If the electricity cost is 50 won / kwh, the annual saving is calculated as \ 20,440 × 50 = 1,022,000 won / year.
 
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